1. The B inside a 100 tums solenoid 4π cm long that carries an current of 10 A is
Answers
Answered by
2
Answer:
Given : l=50 cm=0.5 m i=2.5 A N=100 turns
So, number of turns per unit length n=
l
N
=
0.5
100
=200 turns/m
(i) : Magnetic field inside the solenoid B=μ
o
ni=4π×10
−7
×200×2.5=6.28×10
−4
T
(ii) : Magnetic field at the end of solenoid B
end
=
2
μ
o
ni
=
2
6.28×10
−4
=3.14×10
−4
T
Answered by
2
Answer:
yes yes
when u ask I will give u thanks ok
right that one plz report
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