1. The binding energy for nucleus A is 7.7 MeV and that for nucleus Bis ZS MeV. Which nucleus has the larger mass?
Answers
Answered by
0
Answer:
Binding energy in general is given by, B.E. ={ Mx+My- M(Z,N)}C^2 MeV
Where M(Z,N) is the mass of the original nucleus ,Mx,My are the daughter nuclei.
Now 7.8>7.7------>the mass of the nucleus A seems is the larger Mass!!.But,this is true only if Mx+My is the same for the product nuclei of both A and B,in both cases the mass number(A=Z+N) must be conserved,so if nucleus A is different from nucleus B,it means we have different masses ,so the product nuclei have different masses too, which means the comparison is not correct,which indicates the quesion is wrong.But we know that the binding energy per nucleon(B.E/A) is almost constant around 8MeV.So please review your question
Similar questions