Question

1. The boat goes 30 km upstream and 44 km downstream in 10 hours. In 13 hours, it can go 40 km upstream and 55 km downstream. Determine the speed of stream and that of the boat in still water.

2. A sailor goes 8 km downstream in 40 minutes and returns in 1 hour. Determine the speed of the sailor in still water and the speed of the current.

Hey guys !!
Make it 2 K ♡
Will return it asap.
10 ♡ = 30 ♡
flw = 50 ♡

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Answer 1

Answer:

ok sure bud.dy

Explanation:

Let the speed of boat in still water=x km\hr and The speed of stream=y km\hr

Speed of boat at downstream

⇒(x+y)km/hr

Speed of boat at upstream

⇒(x−y)km/hr

∵

$time = \frac{distance}{time}$

Time taken to cover 30 km upstream ⇒30 / x -1

Time taken to cover 44 km downstream⇒44/ x+y

According to the first condition,

⇒

30/x−y = 44/ x+ 1 =10

Time taken to cover 40 km upstream ⇒ 40/x−y

Time taken to cover 55 km downstream ⇒ 50/x+y

According to the second condition,

⇒

30/x−y = 44/ x+ 1 =13

Let

1/x−y =u and 1/x+y =v

⇒30u+44v=10..eq1

⇒40u+55v=13....eq2

Multiplying eq1 by 3 and eq2 by 5 and subtract both

⇒(150u+220v=50)−(160u+220v=52)

⇒−10u=−2⇒u= 1/5.

put u= 1/5 in eq1

⇒30× 1/5 +44v=10⇒44v=4⇒

v = 1/4

⇒u= 1/x−1 = 1/5

⇒x−y=5 ..eq3

⇒v= 1/ x+y

= 1/11

⇒x+y=11..eq4

Subtracting eq3 and eq4, we get

⇒x=8

Put x=8 in eq3

⇒y=3

Hence, the speed of the boat in still water=8km\hr

The speed of stream=3km\hr

hope it is helpful..