Question

(1)The breadth of a rectangle is 1.28 m and the length of the same is 72 cm more than its breadth. Find out the length of the rectangle in meters.
(2)The perimeter of the above rectangle will be?
(3) If Ahmed doubles the length and keeps the breadth same of the above rectangle, how much will be the area of the rectangle?

Answer 1

Answer:

Answer:1 0.72

2 . 4

3. 1.8432

Step-by-step explanation:

Breadth of rectangle =1.23m

length = 72cm

So length in meters=72/100= 0.72 m

perimeter of rectangle = 2(length + breadth)

=2(1.28+0.72)m

= 4 m

If length is doubled

new length =2.56

Area= 1.8432 m

Answer 2

Step-by-step explanation:

GIVEN:-

Breadth is 1.28 m => 128 cm

Length is 72 cm more than Breadth

ie Length will be 128+72 = 200 cm.

LENGTH = 2metres.

PERIMETER:-

We know that

Perimeter of Rectangle = 2(l +b )

Where l is length

and b is Breadth

P = 2( 200+128)

= 2× 328

PERIMETER = 656 centimetres = 6.56 metres.

When Length is doubled,

that means Length × 2

= 200× 2 = 400 cm is length,

Breadth is same

AREA=?

AREA= L× B

Where L is Length and B is breadth

So placing the values

AREA = 400× 128

AREA = 51200 centimetres

AREA = 512 Metres.