1. The breadth of two rectangles is same which is 10cm. The length of one rectangle is 15cm whose perimeter is half of the perimeter of other rectangle. Find the difference between the perimeters of both the rectangles.
Answers
Answer:
Breadth of the two rectangles = 10cm
Length of one rectangle whose perimeter is half of the perimeter of the other rectangle=15cm
Therefore, perimeter of one rectangle =2×10+15
= 2×25=50cm
According to question, the rectangle with perimeter 50 cm is half of the perimeter of the other rectangle.
Therefore, perimeter of other rectangle = 50×2
=100cm
Therefore difference between the perimeters of both the rectangles = 100cm - 50cm = 50cm
Answer:
length of first rectangle = 15 cm
breadth of rectangle = 10 cm
perimeter = 2( l+b)
=2( 15+10)
=300 cm
let the perimeter of second rectangle be x
ATQ
perimeter of first rectangle= 1/2 x
300= 1/2x
300×2 = x
600 = x
so the perimeter of second rectangle is 600 cm
difference between the perimeters = 600- 300
=300 cm