Question

1.The bromination of 1,3-butadiene results in both 3,4-dibromo-1-butene and 1,4-dibromo-2-butene. Draw all possible stereoisomers of 3,4-dibromo-1-butene that can result from this reaction.

Answer 1

Answer:

CH

2

=CH−CH=CH

2

+Br

2

→BrCH

2

CHBrCH=CH

2

+BrCH

2

CH=CHCH

2

Br

3,4-dibromo-1-butene 1,4-dibromo-2-butene

1,4-dibromo-2-butene is more predominant due to a resonance structure stabilizes the intermediate formed during the reaction.