1. The capacitance between the points A and B of the combination is
A) 9/4 MF
B) 87/12 MF
C) 32/12 MF
D) 92/12 MF
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ans:- C1=C2=C3=C4=C5=4μF. Hence, let us find Cseries−1 and Cseries−2. Hence, the required equivalent capacitance between A and B is 8μF.
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