Question

1. The centroid of a triangle formed by the points (0,0), (cos 7, sin e) and (sin 0, -cos 0) lies on the line y = 2x, then = [ ] a) tan-12 b) tan-1 3 c) tan-'(-3) d) tan-1 (-2)​

Answer 1

Answer:

D is the mid-point of AB D [sin 0+ cos sin 0 2 = - 2 If P is centroid of a AOAB, then P

divides the median OD in the ratio 2:1

=

2 [sin 0 + cos 0 3 2 2 [sin 0 - COS 0 + 2

P [sin + cos sin cos 0 - 3 3 -

Feedback

It is given that centroid lies on line y = 2x

sin Ꮎ - cos Ꮎ 3 [sin 0 + cos 0 3 = 2

without 0

-

cos 2 sin 0 + 2 cos 0

- sin 0 = 3 cos 0

tan 0 =

Ꮎ so ¹ (-3)

Answer 2

sin(180°+3) cot (goº + 8)÷ Sec(-8) + sin^2 8