Question

| 1.
The circumference of the base of a cylindrical vessel is 132 cm and its height is 25 cm
How many litres of water can it hold? (1000 cm³=1 l)​

Answer 1

Answer:

It can hold 34.65L of water.

Step-by-step explanation:

Given -

Circumference = 132 cm

Height [h] = 25 cm.

Consider the -

Radius as - r

As we know,

$\bigstar\;\boxed{\sf Circumference =2\pi r}}$

So,

$\sf \implies 132 = 2 \times \dfrac{22}{7} \times r$

$\sf \implies 132 \times \dfrac{7}{44} = r$

=> r = 21 cm.

Hence,

We got the radius as 21 cm.

Now,

As we know,

$\bigstar\;\boxed{\sf Volume \ of \ cylinder = \pi r^2h}}$

So,

$\sf\\ \\\implies \dfrac{22}{7} \times 21 \times 21 \times 25\\ \\ \implies 34650 cm^3\\ \\\implies 1 cm^3= 0.001 l$

=> 34650 cm³ = 34.65L

Therefore,

It can hold 34.65L of water.

Answer 2

$\huge\sf{Answer:-}$

Given:-

The circumference of the base of a cylindrical vessel is 132 cm and its height is 25 cm.

Find:-

How many litres of water can it hold?

Clue:-

(1000 cm³=1 l)

Formula:-

2 π r = ( Circumference )

Hence:-

$\sf = 132 = 2 \times \frac{22}{7} \times r$

$\sf = 132 \times \frac{7}{44} = r$

$\sf RADIUS= 21 \: cm$

π r² h = ( Volume of the cylinder )

$\sf = \frac{22}{7} \times 21 \times 21 \times 25 \\ \sf = 34650 \: cm {}^{3} \\ 1 \: cm {}^{3} = 0.001 \\ \sf = 34650 \: cm {}^{ 3} = 34.65 \: l$

Therefore, 34.65 is the litres of water it can hold.