Math, asked by friends89, 6 months ago

1. The circumference of the base of a cylindrical vessel is 132 cm and its height is 25 cm.
How many litres of water can it hold? (1000 cm= 11)


2. The inner diameter of a cylindrical wooden pipe is 24 cm and its outer diameter is
28 cm. The length of the pipe is 35 cm. Find the mass of the pipe, if 1 cm' of wood has
a mass of 0.6 g.


3. A soft drink is available in two packs - (i) a tín can with a rectangular base of length
5 cm and width 4 cm, having a height of 15 cm and (ii) a plastic cylinder with circular
base of diameter 7 cm and height 10 cm. Which container has greater capacity and by
how much ?


4. If the lateral surface of a cylinder is 94.2 cm² and its height is 5 cm, then find
(i) radius of its base (ii) its volume. (Use t = 3.14)​

Answers

Answered by mayankkathaitxav
2

Step-by-step explanation:

1.

Circumference of base = 132cm

2\pi \: r \:  = 132

r = 132 \times  \frac{7}{22}

r = 42 \: cm

now Volume of Cylinder =

\pi \: r {}^{2} h

 =  \frac{22}{7}  \times 42 \times 42 \times 25

 = 138600 \: cm {}^{3}

 = 138.6l

2.

Inner diameter=24cm

inner radius =12cm

outer diameter =28cm

outer radius=14cm

let outer radius be R and inner radius be r

so mass of pipe =Outer volume - inner volume

volume of cylinder =

\pi r {}^{2} h

Mass of pipe is equal to =

 \frac{22}{7}   \times 14 \times 14 \times 35 -  \frac{22}{7}  \times 12 \times 12 \times 35

5760 \: cm  {}^{3}

3456 \: g

3.456 \: kg

mass of pipe =

5760 \times 0.6

3.

Volume of tin can with rectangular base

 = l \times b \times h \\ 5 \times 4 \times 15  \\ 300cm {}^{3}

Diameter of tin with cylindrical base =7cm

radius of tin with cylindrical base=3.5cm

volume of tin =

\pi \: r {}^{2}  \times h \\  \frac{22}{7}  \times 3.5 \times 3.5 \times 10 \\ 385 \: cm {}^{3}

Therefore the thin with cylindrical base has more capacity by 85 cm cube

4.

Lateral surface area of cylinder

94.2 \: cm { }^{2}

2\pi \: r \: h \:  = 94.2 \\ 2 \times  3.14  \times 5 = 94.2 \\ r = 94.2 \times   \frac{1}{3.14}  \times  \frac{1}{5}  \times  \frac{1}{2 }  \\ r = 3cm

Volume of cylinder

\pi \: r {}^{2} h \\  3.14 \times 3 \times 3 \times 5 \\ 141.3cm {}^{3}

I wish it would help you!!!

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