Math, asked by kumariharshita828, 5 hours ago

1. The coefficient of x in the product (2-3) (
526) is
(a) 19
(5) - 19
(c) 15
(0) 6
2. 13x +ka? 8 = (3x-2)(x + 4) for all x, then the value of k is
(a) -2
(1) 12
(c) 10
(d) 8
3. The coefficient of in (3x++) (+)
is
(d) 2
(a) 3
(b) 1
(c) 4
4. If a = 3 + b3 prove that a-b-9ab27.
(a?-?) + (b2-c?) +(-a?!
5. Simplify:
(a - b)+(b-c)+(c-a)
1
6. If a + + 0, then the value of (a + 2) +-1
(a+2)
(a +2)
(a) 6
(6) 4
(c) 3
7. If a+++2=0, then the value of (o is
is
(d) 2
37
100
(d) 2
(c) 1
(b) -2
(a) 0





please answer fast please
I will mark you as brainilist ​

Answers

Answered by raxneha
1

Answer:

Step-by-step explanation:

The general term in the expansion of (2−x+3x  

2

)  

6

 is

r!s!t!

6!

2  

r

(−x)  

s

(3x  

2

)  

t

, where r+s+t=6

=  

r!s!t!

6

2  

r

×(−1)  

s

×3  

t

×x  

s+2t

,

where r+s+t=6

For the coefficient of x  

5

, we must have

s+2t=5

But r+s+t=6

∴s=5−2t and r=1+t

where, 0≤r,s,t≤6

Now, t=0⇒r=1,s=5

t=1⇒r=2,s=3

t=2⇒r=3,s=1

Thus, there are three terms containing x  

5

 and coefficient of x  

5

 

=  

1!5!0!

6!

×2  

1

×(−1)  

5

×3  

0

+  

2!3!1!

6!

×2  

2

×(−1)  

3

×3  

1

+  

3!1!2!

6!

×2  

3

×(−1)  

1

×3  

2

 

=−12−720−4320

=−5052.

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