Question

1) the coefficient of x in the quadratic equation x^2+px+q=0 was taken as 17 in place of 13, its roots were found to be -2 and -15. find the roots of the original equation.​

Answer 1

Step-by-step explanation:

given x^2+px+q=0 where p=17 nd roots are -2,-15

product of roots= c/a

-2 x -15 = q/1

30 = q

Then the required equation is,

x^2+13x+30=0

if we solve we get roots -3,-10

Answer 2

Answer:

x = -3 , -10

Step-by-step explanation:

Check the attachment

Hope it helps