1. The cost
by 6% every year. If its current price is
2500, what will be its price after 3 years?
2. A car was bought in current 2015
for 3,00,000. If the value of the car
depreciates by 5% each year, find its
worth in the year 2018.
3. An engineering college has 5,000 students
in 2016. If the strength of the students
increases at a rate of 4% every year, find
the number of students in 2018.
4. In 2016, the number of tourists who
visited a hill station was 50,00,000. It
increased by 4% every year following
2016. Find the number of tourists who
visited the hill station in 2019.
5. The price of a mobile phone depreciates
at a rate of 6% every year. If its current
cost is 20,000, what will be its price
after 4 years?
Answers
Answered by
3
Answer:
Price After two year =4,20,000
let price after one year =x
x
x−420,000
×100=20
x=
4
5
×420,000
x=525,000
let price (original ) =y
y
y−525,000
×100=20
y=
4
5
×525,000
y=656,250
Answered by
10
Answer:
Answer:
Price After two year =4,20,000
let price after one year =x
x
x−420,000
×100=20
x=
4
5
×420,000
x=525,000
let price (original ) =y
y
y−525,000
×100=20
y=
4
5
×525,000
y=656,250
Answered by
5
Answer:
Answer:
Price After two year =4,20,000
let price after one year =x
x
x−420,000
×100=20
x=
4
5
×420,000
x=525,000
let price (original ) =y
y
y−525,000
×100=20
y=
4
5
×525,000
y=656,250
Answered by
6
Answer:
Answer:
Price After two year =4,20,000
let price after one year =x
x
x−420,000
×100=20
x=
4
5
×420,000
x=525,000
let price (original ) =y
y
y−525,000
×100=20
y=
4
5
×525,000
y=656,250
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