Question

1). The cost of 2 kg of apples and 1 kg of grapes on a day was found to be 160 rupees. After a month the cost of 4 kg of apples and 2 kg of grapes is 300 rupees. Represent the situation algebraically and geometrically.​

Answer 1

$Let cost each kg of apples = Rs x</p><p>Cost of each kg of grapes = Rs y</p><p>Given that The cost of 2 kg of apples and 1kg of grapes on a day was found to be Rs 160</p><p>So that</p><p>2 x + y = 160 … (1)</p><p>2x = 160 - y</p><p>x = (160 – y)/2</p><p>Let y = 0 , 80 and 160 we get</p><p>X = (160 – ( 0 ))/2 = 80</p><p>X = (160- 80 )/2 = 40</p><p>X = (160 – 2* 80 )/2 = 0</p><p>X</p><p>80</p><p>40</p><p>0</p><p>y</p><p>0</p><p>80</p><p>160</p><p>Given that the cost of 4 kg of apples and 2 kg of grapes is Rs 300</p><p>so we get</p><p>4 x + 2 y = 300 … (2)</p><p>Divide by 2 we get</p><p>2 x + y = 150</p><p>Subtract 2x both side we get</p><p>Y = 150 – 2 x</p><p>Plug x = 0 , 50 , 100 we get</p><p>Y = 150 – 2*0 = 150</p><p>Y = 150 – 2* 50 = 50</p><p>Y = 150 – 2 * (100 ) = - 50</p><p>X</p><p>0</p><p>50</p><p>100</p><p>Y</p><p>150</p><p>50</p><p>-50</p><p>Algebraic representation</p><p>2 x + y = 160 … (1)</p><p>4 x + 2 y = 300 … (2)</p><p>The cost of 2 kg of apples and 1kg of grapes on a day was found to be Rs 160.</p><p>$

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Answer 2

Answer:

2x+y=160

4x+2y=300

Step-by-step explanation:

Let the cost of 1 kg of Apples be Rs x

and the cost of 1 kg of Grapes be Rs y

According to question,

On a particular day,

2x+y=160

After a month,

4x+2y=300

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