Question

1. The denominator of a fraction is 3times the numerator. If 2 is
added to the numerator and 3 is
added to the denominator, then the
denominator of the new fraction
becomes 2 times the numerator.
Find
the original fraction.​

Answer 1

Given :-

• The denominator of a fraction is 3times the numerator.

• If 2 is added to the numerator and 3 is added to the denominator, then the denominator of the new fraction becomes 2 times the numerator.

To Find :-

• What is the original fraction?

Solution :-

Let the numerator of the fraction be x.

Then, the denominator of the fraction will be 3x.

As per question :-

Given that,

If 2 is added to the numerator and 3 is added to the denominator, then the denominator of the new fraction becomes 2 times the numerator.

Therefore,

(x +2) / (3x +3) = y/2y

⟼ 3x +3 = 2x +4

⟼ 3x -2x = 4-3

$⟼x = 1$

Hence,

the numerator of the fraction will be = 1

The denominator of the fraction will be

= 3x

= 3 ×1

=3

Therefore, the original fraction is = 1/3

Answer 2

Answer:

The denominator of a fraction is 3times the numerator.

• If 2 is added to the numerator and 3 is added to the denominator, then the denominator of the new fraction becomes 2 times the numerator.

To Find :-

• What is the original fraction?

Solution :-

Let the numerator of the fraction be x.

Then, the denominator of the fraction will be 3x.

As per question :-

Given that,

If 2 is added to the numerator and 3 is added to the denominator, then the denominator of the new fraction becomes 2 times the numerator.

Therefore,

(x +2) / (3x +3) = y/2y

⟼ 3x +3 = 2x +4

⟼ 3x -2x = 4-3

⟼x = 1⟼x=1

Hence,

the numerator of the fraction will be = 1

The denominator of the fraction will be

= 3x

= 3 ×1

=3

Therefore, the original fraction is = 1/3