Math, asked by ratansingh2, 1 year ago

1.the diagonal of a rectangular field is 60meter more than the shorter side. if the longer side is 30 metres more than the shorter side find the sides of the field.

2. the difference of squares of two number is 180. the square of the smaller number is 8 times the larger number.find the two numbers.

Answers

Answered by jkhan1
19
hey dear here is ur answer

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1. let be shorter side =X
diagonal side=X+60
longer side= X + 30

by applying Pythagoras theorem;

(X + 60)²= (X + 30)²+x²

X² + 3600+120x=x²+ 900 + 60 x +x²
x²+3600+120x-x²-900-60x-x²=0
-x²+60x+2700=0

x²-60x+2700=0
x²-x(90-30)-2700=0
X²-90x+30x-2700=0
X(x-90)+30(x-90)=0

(x-90) (X+30)
x-90=0. X+30=0
X=90 X=-30(side can not be negative

hence,
shorter side=90m.
longer side=90+30=120m.

ShaadabShamim: Mate, your given answer is wrong.
ShaadabShamim: Refer To My Answer And Check It.
ShaadabShamim: And you haven't even mentioned about the second answer.
jkhan1: I'm anable to send the second answer, if i get another chance to edit the answer then, i will sure send. ohk.
ratansingh2: ohk thank
ratansingh2: ur answer is right
jkhan1: ur wlcm deaR ✌✌. :-)....
ShaadabShamim: Hey!!!
ShaadabShamim: Ur answer is wrong.
ShaadabShamim: Mine Is Right.
Answered by ayush0017
1

Answer:

90 m and 120m

Step-by-step explanation:

let be shorter side =X

diagonal side=X+60

longer side= X + 30

by applying Pythagoras theorem;

(X + 60)²= (X + 30)²+x²

X² + 3600+120x=x²+ 900 + 60 x +x²

x²+3600+120x-x²-900-60x-x²=0

-x²+60x+2700=0

x²-60x+2700=0

x²-x(90-30)-2700=0

X²-90x+30x-2700=0

X(x-90)+30(x-90)=0

(x-90) (X+30)

x-90=0. X+30=0

X=90 X=-30(side can not be negative

hence,

shorter side=90m.

longer side=90+30=120m

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