Question

1/the diagonal of a rhombus measure 24cm and 10cm.find its perimeter.

2/ find the perimeter of a rectangle whose length is 40cm and the length of one of the diagonal is 41cm

Answer 1

Hey dear!


Here is yr answer.......


1.

Let us take rhombus ABCD

AC & BD are diagonals

O is the midpoint of rhombus

AC = 24cm (given)

BD = 10cm (given)


AO = OC = 12cm

BO = OD = 5cm


Now, in Rhombus AOB -----

using pythagorus therom!


AB² = AO² + BO²

AB² = 12² + 5²

AB² = 144+25

AB = √169

AB = 13cm



Now,

Perimeter of rhombus = 4s

= 4(AB)

= 4(13)

= 52cm


Therefore, perimeter of rhombus = 52cm


_____________________________


2.


Let us take rectangle ABCD

length = 40cm

AC is a diagonal of 41cm


Now,

Using pythagorous therom!


BC² = AC² - AB²

BC² = 41² - 40²

BC² = 1681 - 1600

BC = √81

BC = 9cm



Perimeter of rectangle = 2(l+b)

= 2(40+9)

= 2(49)

= 98cm


Therefore, perimeter of rectangle = 96cm



Hope it hlpz....