Question

1. The displacement of a particle in SHM is given by
y eqal to 5 sin pi t +pi /6
Find its maximum acceleration and initial displacement​

Answer 1

Answer:

x=5sinπt+12sin(πt+π/2)

=5sinπt+12cosπt

=13sin(πt+θ) where cosθ=5/12

Amplitude, A=max(x)=13 cm

Time period, T=2π/ω=2π/π=2 s

Initial phase, α=∠(x)

t=0 =θα=cos −1 (5/12)

Explanation:

Hope this helps you buddy ✌️✌️