1. The displacement of a particle in SHM is given by
y eqal to 5 sin pi t +pi /6
Find its maximum acceleration and initial displacement
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Answer:
x=5sinπt+12sin(πt+π/2)
=5sinπt+12cosπt
=13sin(πt+θ) where cosθ=5/12
Amplitude, A=max(x)=13 cm
Time period, T=2π/ω=2π/π=2 s
Initial phase, α=∠(x)
t=0 =θα=cos −1 (5/12)
Explanation:
Hope this helps you buddy ✌️✌️
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