Question

1. The displacement x of a particle at time t along a
straight line is given by x = a -ßt + y +2. Find the
acceleration of the particle.
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Answer 1

Answer:

=t

=t 3

=t 3 −6t

=t 3 −6t 2

=t 3 −6t 2 +3t+4⇒v=3t

=t 3 −6t 2 +3t+4⇒v=3t 2

=t 3 −6t 2 +3t+4⇒v=3t 2 −12t+3

=t 3 −6t 2 +3t+4⇒v=3t 2 −12t+3a=dv/dt=6t−12=0⇒t=2s

=t 3 −6t 2 +3t+4⇒v=3t 2 −12t+3a=dv/dt=6t−12=0⇒t=2sv=3(2)

=t 3 −6t 2 +3t+4⇒v=3t 2 −12t+3a=dv/dt=6t−12=0⇒t=2sv=3(2) 2

=t 3 −6t 2 +3t+4⇒v=3t 2 −12t+3a=dv/dt=6t−12=0⇒t=2sv=3(2) 2 −12×2+3=−9ms

=t 3 −6t 2 +3t+4⇒v=3t 2 −12t+3a=dv/dt=6t−12=0⇒t=2sv=3(2) 2 −12×2+3=−9ms −1

Answer 2

Answer:

s=t

3

−6t

2

+3t+4⇒v=3t

2

−12t+3

a=dv/dt=6t−12=0⇒t=2s

v=3(2)

2

−12×2+3=−9ms

−1