Question

1. The displacement x of a particle moving in one dimension under the action of constant force is related to time t by the equation t = VX + 3, where x is in metres and t is in seconds. Find the displacement of the particle when its velocity is zero:- (1) zero (2) 12m (3) 6m (4) 18m

Answer 1

Answer:

$\underline{\Huge{\texttt{0 (Option (1))}}}$

Explanation:

$t = \sqrt x+3\\\sqrt x = t-3\\x = t^2 - 6t + 9$

$dx/dt$ is the velocity.

$dx/dt = 2t -6\\v = 0\\2t-6 = 0$

Which will give us $3$ so $t = 3$

at $t = 3$

$x = 3-3$

So there will be $0$ displacement.

Answer 2

Answer:

(1) zero

Explanation:

We know that,

velocity = displacement ÷ time

or, displacement = velocity × time

where, velocity = 0

So, displacement = 0