Chemistry, asked by balu9286, 11 months ago

1. The emf of the cell,
NEN2+ (IM)||Ag* (1M) | Ag
E for N /N = -0.25 volt. E for Ag* /Ag = 0.80 volt ) is given by
1) -0.25 +0.80 =0.55 volt 2) -0.25 - (+0.80) = -1.05 volt
30-0.80.1-0.25) = +1.05 volt 4) -0.80 - (-0.25) = -0.55 volt​

Answers

Answered by aryantripathy857
1

Answer:

0.555 volts is the answer

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