Question

1) The equilibrium for the dissociation of XY, is given as, . 2XY, (g) = 2XY (g) + Y,(g) 2​

Answer 1

hi Akka eppdi irukinga

The equilibrium for the dissociation of XY2 is given as, 2XY2(g) ⇌ 2XY(g) + Y2(g). If the degree of dissociation x is so small compared to one. Show that 2 KP = Px3 where P is the total pressure and K is the dissociation equilibrium constant of XY2 .

Answer 2

The equilibrium for the dissociation of XY2

Is given as, 2XY2(g) ⇌ 2XY(g) + Y2(g).

If the degree of dissociation x is so small compared to one.

Show that 2 KP = Px3 where P is the total pressure and K is the dissociation equilibrium constant of XY2.

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