Question

1. The factorisation of (x++2)y+(x+2)x is
2.The factorisation of (x-y)²+(x-y) is
please answer the questions

Answer 1

1. The given expression:

(x + 2)y + (x + 2)x

We have to find, the factorisation of the given expression.

Solution:

The given expression is:

(x + 2)y + (x + 2)x

Taking (x + 2) as common, we get

= (x + 2)[y + x)

= (x + 2)(x + y)

∴ The factorisation of the given expression = (x + 2)(x + y)

2. The given expression:

$(x-y)^{2}$ + (x - y)

We have to find, the factorisation of the given expression.

Solution:

The given expression is:

$(x-y)^{2}$ + (x - y)

=  (x - y)(x - y) + (x - y)

Taking (x - y) as common, we get

= (x - y)[(x - y) +1]

= (x - y)(x - y + 1)

∴ The factorisation of the given expression = (x - y)(x - y + 1)

Answer 2

Given :  (x + 2)y + (x + 2)x

(x - y)² + (x - y)

To Find : Factorize

Solution:

(x + 2)y + (x + 2)x

Taking (x + 2) common

= (x + 2)(y + x)

= (x + 2)(x + y)

= (x + y)(x + 2)

=> (x + 2)y + (x + 2)x  = (x + y)(x + 2)

(x-y)²+(x-y)

=  (x-y)(x-y)  + (x - y).1

Taking (x - y) common

= (x - y)(x - y + 1)

= (x - y) (x - y + 1)

=>   (x-y)²+(x-y)  = (x - y) (x - y + 1)

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