Question

1. The first four terms of a sequence are
T1=1^2
T2 = 1^2+ 2^2
T3= 1^2+ 2^2 +3^2
T4=T3= 1^2+ 2^2 +3^2 +4^2
a) The nth term is given by Tn =
1/6 n(n+1) (2n+1).

Work out the value of T23.

Answer 1

Answer:

T24 = 1/6(24)(25)(47) = 25944/6 = 4324