Question

1. The following compounds are given to you: 2-Bromopentane, 2-Bromo-2-methylbutane, 1-
Bromopentane
(a) Write the compound which is most reactive towards SN2 reaction.
b) Write the compound which is optically active.
(c) Write the compound which is most reactive towards B-elimination reaction​

Answer 1

Answer:

Explanation:

(a) 1- Bromopentane is most reactive towards SN2 reaction.

(b) 2-Bromo-2-methylbutane

(c) 2- Bromopentane is most reactive towards β-elimation reaction with product of pent-1-ene pent-2-ene.

Answer 2

(a) The compound 1- Bromopentane ( CH$_{3}$CH$_{2}$CH$_{2}$CH$_{2}$CH$_{2}$Br )  is most reactive towards SN$_{2}$ reaction. due to the presence of one degree of carbon attached to the bromine atom .

(b) The compound 2-Bromo-2-methylbutane  is optically active due to the presence of chiral carbon in the compound .

(c) The compound 2- Bromopentane ( CH$_{3}$CHBrCH$_{2}$CH$_{2}$CH$_{3}$ ) is most reactive towards the β-elimination reaction . Pent-2-ene will be formed .