Science, asked by angelamariaisabelavi, 2 months ago

1.The following terrestrial plants have leaves that remain green almost all year round EXCEPT _____.
A.Pepper plant B. Rubber tree C. Rice plant D. Tobacco plant

2. A duckweed plant is an example of aquatic plant. What could be its characteristics? It .. A. can float on water. B. can be planted in soil C. can allow water to flow on it. D. is light, spongy and float on the surface of the water. 3.Why do plants have specialized structures? Because plants ... A. need care. B. are living things. C. are non-living things. D. need these to survive from their environment. PLS ANSWER IT °Δ°

Answers

Answered by theshahinaelsa786
1

Answer:

1)

ans: D. Tobacco plant

2)

ans: A. can float on water

3)

ans: D.need these to survive from their environment

Answered by gouravgupta65
1

Explanation:

a

3

a

3

1

+2=

8

3

Step-by-step explanation:

If

\begin{gathered}2a - \frac{2}{a} + 1 = 0...eq1 \\ \end{gathered}

2a−

a

2

+1=0...eq1

then to find the value of

\begin{gathered} {a}^{3} - \frac{1}{ {a}^{3} } + 2 \\ \\ \end{gathered}

a

3

a

3

1

+2

take cube of eq1

\begin{gathered}2a - \frac{2}{a} = - 1 \\ \\ a - \frac{1}{a} = \frac{ - 1}{2} \\ \\ {(a - \frac{1}{a}) }^{3} = {( \frac{ - 1}{2} )}^{3} \\ \\ {a}^{3} - \frac{1}{ {a}^{3} } - 3 {a}^{2} ( \frac{1}{a} ) + 3a( \frac{1}{ {a}^{2} } ) = - \frac{1}{8} \\ \\ {a}^{3} - \frac{1}{ {a}^{3} } - 3a + \frac{3}{a} = \frac{ - 1}{8} \\ \\ {a}^{3} - \frac{1}{ {a}^{3} } - 3(a - \frac{1}{a}) = \frac{ - 1}{8} \\ \\ {a}^{3} - \frac{1}{ {a}^{3} } - 3( - \frac{1}{2}) = \frac{ - 1}{8} \\ \\ {a}^{3} - \frac{1}{ {a}^{3} } + \frac{3}{2} = \frac{ - 1}{8}\end{gathered}

2a−

a

2

=−1

a−

a

1

=

2

−1

(a−

a

1

)

3

=(

2

−1

)

3

a

3

a

3

1

−3a

2

(

a

1

)+3a(

a

2

1

)=−

8

1

a

3

a

3

1

−3a+

a

3

=

8

−1

a

3

a

3

1

−3(a−

a

1

)=

8

−1

a

3

a

3

1

−3(−

2

1

)=

8

−1

a

3

a

3

1

+

2

3

=

8

−1

\begin{gathered}{a}^{3} - \frac{1}{ {a}^{3} } + 2 = \frac{ - 1}{8} - \frac{3}{2} + 2 \\ \\ = \frac{ - 1 - 12 + 16}{8} \\ \\ {a}^{3} - \frac{1}{ {a}^{3} } + 2 = \frac{3}{8} \\ \\ \end{gathered}

a

3

a

3

1

+2=

8

−1

2

3

+2

=

8

−1−12+16

a

3

a

3

1

+2=

8

3

Hope it helps you.

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