Question

1. The fourth term of an arithmetic sequence is 20, and the 13th term is 65. Write the first 6 terms of the sequence. ​

Answer 1

Answer:

A.P. = 5 , 10 , 15 , 20 , 25 , 30 ...........

Step-by-step explanation:

Let first term be a and common difference be d

4th term = 20

a + (4 - 1) d = 20

a + 3d = 20     .........(1)

13th term = 65

a + (13 - 1) d = 65

a + 12d = 65     ...........(2)

From 1 and 2 we get,,

d = 5 and a = 5

A.P. = 5 , 10 , 15 , 20 , 25 , 30 ...........

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