1. The fourth term of an arithmetic sequence is 20, and the 13th term is 65. Write the first 6 terms of the sequence.
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Answer:
A.P. = 5 , 10 , 15 , 20 , 25 , 30 ...........
Step-by-step explanation:
Let first term be a and common difference be d
4th term = 20
a + (4 - 1) d = 20
a + 3d = 20 .........(1)
13th term = 65
a + (13 - 1) d = 65
a + 12d = 65 ...........(2)
From 1 and 2 we get,,
d = 5 and a = 5
A.P. = 5 , 10 , 15 , 20 , 25 , 30 ...........
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