Question

1. The frame of brass plate of an outer door design has area 1.60 m² and thickness 1 cm. The brass plate experiences shear force due to earthquake. How large a parallel force must be exerted on each of its edges, if the lateral displacement is 0.32 mm? ( $\eta_{brass}$ = 3.5 x 10¹⁰ N / m²) (Ans : 1.792 x 10⁹ N)

Answer 1

Given :

Area=A = 1.60m² ,  

η brass= η=3.5 × 10¹⁰N/m²  

x = 0.32 mm = 0.32 × 10⁻³ m,  

h = 1 cm = 1 × 10⁻² m

η = Fh /Ax

∴ F = ηxA/ h

= 3.5 x10 ¹⁰x0.32x1.6/1x10⁻²

∴ F = 1.792 × 10⁹ N

Answer 2

Answer:

Given :

Area=A = 1.60m² ,  

η brass= η=3.5 × 10¹⁰N/m²  

x = 0.32 mm = 0.32 × 10⁻³ m,  

h = 1 cm = 1 × 10⁻² m

η = Fh /Ax

∴ F = ηxA/ h

= 3.5 x10 ¹⁰x0.32x1.6/1x10⁻²

∴ F = 1.792 × 10⁹ N