Question

1. The GI of cyclopentyl methanal will be -
() Primary alcohol (b) secondary alcohol (c) Tertiary alcohol (d) None of these
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Answer 1

Answer:

A)

Explanation:

In methanal, both R groups are hydrogen. Methanal is the simplest possible aldehyde HCHO. Assuming that we are starting with CH

3

CH

2

MgBr. Since both R groups are hydrogen atoms, the final product will be a primary alcohol. A primary alcohol is formed. A primary alcohol has only one alkyl group attached to the carbon atom with the −OH group on it.