Math, asked by sriamarwebz, 5 months ago

1.The graph of the linear equation 4x=6 is parallel to which axis?

2.Point (a,0) lie on which axis?

3.Write the equation of x axis.

4.Write a linear equation of two variables for x=5, y=-2.

5.Find the value of K, if x=-1 is a solution of equation Kx-2y=0.

6.Write the linear equation which is parallel to x-axis and is at a distance of 2 units from the origin in upward direction.

7.How many solutions are there for equation y=5x+2.

8.Express the equation 5y=9 as linear equation in two variables.

9.If the graph of equation 2x+Ky=10 K intersects x axis at point (5,0) find the value of K.

10.Express the linear equation
sqrt{2x} - 4 =5y
in the form of ax+by+c=0 and thus indicate the values of a,b and c

Answers

Answered by shivangiroy27
6

Answer:

■ we have 4x=6

=x =6/4

=x =3/2

so it will be a parllel to y-axis and passing through x=3/2

■ the given point lies on x-axis

■ the equation of x-axis is y = 0.

■ x=5   ,  y=2

x+y=5+2(2)=9

5x+2y=5(5)+2(2)=29

x+y=7

5x+y=5(5)+2=27

x=5,y=2 is solution of x+y=7

■ k(2^2)+2(2)-3=0

4k+4-3=0

4k+1=0

4k= -1

k= -1/4

■ The equation of a straight line parallel to x − axis at a distance 2 units from the origin is:

y = 2

■ The lines are parallel, so there is no intersection, therefore no solution.

Explanation:

this equation are for straight lines because they are in the form y=mx+c

However, they have the same slope. m=5, which means that these lines are parallel.

Parallel lines never intersect, so there is no solution for this equations.

■ 0x + 5y -9=0

■ The line is given to pass through (2, 0). If we put x = 2 and y = 0, then equation will hold. So

2(2) + k(0) = 10k

k = 4/10 = 2/5

■ root 2x-4=5y

root 2x-5y-4=0

so,

a=2

b= -5

c= -4


sriamarwebz: Thank you very much for this answer.
Answered by Anonymous
2

Answer:

Explanation:

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