1. The heat loss h (in Watts) through a single-pane glass window varies jointly with the window’s area A (in square metres) and the difference between the inside and outside temperatures d (in Kelvins).
(a) Write an equation relating h, A, d, and a constant, k.
(b) A single-pane window with an area of 1 square metre and a temperature difference of 1 Kelvin has a heat loss of 5.7 Watts. What is the heat loss through a single-pane window with an area of 2.5 square metres and a temperature difference of 20 Kelvins?
This is a math word problem on variables please answer it like a math problem, not a science problem. Thanks.
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Answer:
a) h=kAd, b) 285 Watts
Step-by-step explanation:
Heat loss- h, Window's are- A, Temperature difference- d, Constant- k
h varies jointly with A and d, then the equation will be:
- a) h=k*Ad
- b) A= 1 m², d= 1 Kelvin, h= 5/7 Watts
Equation will reflect this as:
- 5.7=k* 1*1 => k=5.7
When A= 2.5 m², d= 20, h=?
- h=kAd= 5.7*2.5*20= 285 Watts
Answer: a) h=kAd, b) 285 Watts
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