Question

1. The height (in meters) of a projectile shot vertically upward from a point 2 m above ground level with an initial velocity of 22.5 m/s is h = 2 + 22.5t - 4.9t^2 after t seconds. (a) Find the veloci

Answer 1

The height (in meters) of a projectile shot vertically upward from a point 2 m above ground level with an initial velocity of 22.5 m/s is h=2+22.5t−4.9t2 h = 2 + 22.5 t − 4.9 t 2 after t seconds.