Math, asked by Stannei, 2 days ago

1 The hungry cat is trying to catch Kunjan the mouse. Kunjan is now on the 14th step and it can jump 2 steps at a time. The cat is on the third step. She can jump 3 steps at a time. If the mouse reaches 28 it can hide in the hole. Find out whether the mouse can get away safely!​

Answers

Answered by shamika91
0

Answer:

The answer is yes it the mouse can get to safety.

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Step-by-step explanation:

1. Kunjan is at 14th step and the hungry cat at 3rd.

2. So to reach 28th step to safety he has to jump 7 times (14 x 2 =28 so, 14 divided by 2 = 7)

3. If the cat jumps 7 times too she reaches the 21st step (3 x 7 = 21)

So the mouse can get away safely

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