Question

1. The hypotenuse of a right triangle is 17 cm long. If one of the remaining two sides is 8 cm in
length, then the length of the other side is
(0) 15 cm (b) 12 cm
(c) 13 cm
(d) none of these



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Answer 1

Step-by-step explanation:

ANSWER

Let one side be xcm.Since the difference between the two sides is 7cm

∴ the other side=x+7cm

As the given triangle is a right angled triangle with hypotenuse =17cm

By using pythagoras theorem, we get

x

2

+(x+7)

2

=17

2

⇒x

2

+x

2

+14x+49−289=0

⇒2x

2

+14x−240=0

⇒x

2

+7x−120=0

⇒x

2

+15x−8x−120=0

⇒x(x+15)−8(x+15)=0

⇒(x+15)(x−8)=0

⇒x=−15 or x=8

x=−15 cannot be negative

∴x=8

Hence the two sides of the triangle are 8cm and 15cm

Answer 2

Answer:

Step-by-step explanation:

$(hyp)^{2}$=$(base)^{2}$+$(perp)^{2}$

$17^{2}$ = $8^{2}$ + $(perp)^{2}$

289 = 64 +$(perp)^{2}$

$(perp)^{2}$ = 289 - 64

perp = $\sqrt{225}$

perp = 15