1. The inner diameter of a circular well is 3.5 m. It is 10 m deep. Find
0 its inner curved surface area,
(i) the cost of plastering this curved surface at the rate of 40 per m².
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• Given
- Inner diameter of a circular well = 3.5 m
- Depth of a circular wall = 10 m
• To find
- Its inner curved surface area
- Cost of this curved surface at the rate of 40 per m².
• Solution
• Inner curved surface area = 2πrh
where,
- r = radius of the well
- h = height of the well
- Take π = 22/7
• Diameter = 3.5 m
⇒ Radius = Diameter/2
⇒ 3.5/2
⇒ 1.75 m
Substitute the given values,
⇒ 2 × 22/7 × 1.75 × 10
⇒ 110 m²
• Inner curved surface area = 110 m²
(ii) Cost of this curved surface at the rate of 40 per m².
⇒ 110 × 40
⇒ Rs. 4400
• Cost of this curved surface at the rate of 40 per m² = Rs. 4400
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