Question

1.The irreducible factorisation of 3a^3 + 6a is

(a)3a (a^2 + 2)

(b) 3 (a^3 + 2)

(c) a (3a^2 + 6)

(d) 3 × a × a × a + 2 × 3 × a​

Answer 1

Answer:

(a) 3a (a²+2)

because the 3 and 'a' is common by 3a³ + 6a

Answer 2

Step-by-step explanation:

option is the right answer