Question

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1) The K.E of a body becomes twice it's initial value.


=> find the new momentum of the body ???


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$<h1><marquee><font color = red > prabhudutt$

Answer 1

your answer is ----


firstly we state relation between kinetic energy and momentum


K.E = 1/2 mv^2

where ,

K.E = kinetic energy

m = mass

v = velocity

multiply both side by mass m , we get

K.E × m = 1/2 (mv)^2

=> 2m K.E = (mv)^2

°•° mv = momentum = p

=> p = √(2mK.E)


if kinetic energy become double , then it's momentum is

=> p = √(2m×2K.E

=> p = √(4mK.E

=> p = 2√K.Em

Answer 2

your answer is ----

firstly we state relation between kinetic energy and momentum

K.E = 1/2 mv^2

where ,

K.E = kinetic energy

m = mass

v = velocity

multiply both side by mass m , we get

K.E × m = 1/2 (mv)^2

=> 2m K.E = (mv)^2

°•° mv = momentum = p

=> p = √(2mK.E)