Physics, asked by ramanikalla, 9 months ago

1)The kinetic energy of an object is 4 J mass of an object is 4 kg find the velocity and momentum?

2)The force acting on the system is 20 N then the mass of the object is 30 kg find the Acceleration?

3)When an object is at rest the mass of the object is 5kg applied force is 50 N in 1 min find the final velocity?

IF ANYONE ANSWER THESE 3 QUESTIONS I WILL MARK THEM AS BRAINLIST AND SAY THANKS AND FOLLOW THEM AND GIVE 5 STAR.

Answers

Answered by Anonymous
40

Answer 1 :-

Given :-

  • Kinetic Energy (K.E) = 4 J
  • Mass (m) = 4 kg

To Find :-

  • Velocity (v)
  • Momentum (p)

So, first let's find Velocity

Formula Used :-

  • K.E = ½ mv²

Subsituting Values

→ 4 = ½ × 4 × v²

→ 4 = 2 × v²

→ 4 - 2 = v²

→ 2 = v²

→ v = √2

So, the final velocity is √2

Now, let's find momentum

Formula Used :-

  • p = m × v

Subsituting Values

→ p = 4 × √2

→ p = 4√2

So, the momentum is 4√2

Answer 2 :-

Given :-

  • Force (F) = 20 N
  • Mass (m) = 30 kg

To Find :-

  • Acceleration (a)

So, finding it

Formula Used :-

  • F = m × a

Subsituting Values

→ 20 = 30 × a

→ 20 = 30a

→ 30a = 20

→ a = 20/30

→ a = 2/3

→ a = 0.66

So, the acceleration is 0.66 m/s²

Answer 3 :-

Given :-

  • Initial Velocity (u) = 0 m/s (as it's on rest)
  • Mass (m) = 5 kg
  • Force (F) = 50 N
  • Time (t) = 1 min = 60 s

To Find :-

  • Final Velocity

Finding Final Velocity

Formula Used :-

  •  \red{ \rm F = m \Bigg( \dfrac{v-u}{t} \Bigg) }

Subsituting Values

 \sf 50 = 5 \Bigg( \dfrac{v-0}{60} \Bigg)

\sf 50 =  \dfrac{5v-0}{60}

\sf 50  \times 60=  5v-0

\sf 3000=  5v

\sf   5v = 3000

\sf   v =  \cancel{ \dfrac{3000}{5} }

\sf   v  = 6

Thus, the final velocity is 6 m/s

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