Question

1. The kinetic energy of an object of mass 'm' moving with a velocity of 5 m s' is 25 J. What will be its
kinetic energy when its velocity is doubled? What will be its kinetic energy when its velocity is increasedthree times?​

Answer 1

Answer:

Kinetic Energy,K=½×mv²

Given

initial kinetic energy = 25J

When velocity is doubled,

New velocity,V=2v

Kinetic energy=½ m(2v)²

=4×25J

=100J

When velocity is made three times ,

New velocity ,v = 3v

Kinetic energy = ½ m(2v)²

=½×m×9×v²

=9(½mv²)

but Kinetic energy=½mv²=25J

=9×25

=225J