Question

1. The kinetic energy of an object of mass, m moving with a velocity of 5 m/s is 25 J.
what will be its kinetic energy when its velocity is doubled? What will be its kinetic
energy when its velocity is increased three time​

Answer 1

Explanation:

1st K.E. = 1/2 × m × v^2

25 J = 1/2 × m × 25

25 × 2 /25 = m

2 kg = m

Now velocity is 5×3 = 15. Hence, new kinetic energy is

1/2 × 2 × 15 × 15

Answer 2

Answer:

Kinetic Energy is 100J when it is doubled

Kinetic Energy is 225J when it is increased by three times

Explanation:

v=5m/s

K.E=25J

K.E=½mv²

25=½ × m × 5 × 5

m=2

When velocity Is Doubled,

v=5×2=10m/s

K.E=½ × 2 × 10 × 10

K.E = 100J

When velocity is increased by three times,

v=5×3=15m/s

K.E=½ × 2 × 15 × 15

K.E=225J