Question

1.
The LCM of two numbers is 96 and their HCF is 8. If one of the numbers is 32, find the other
number.
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Answer 1

Answer:

let one number be n

lcm×hcf= 32×n

96×8÷32=n

n=24

Step-by-step explanation:

I hope it helps you and

Answer 2

Answer:

Let one number be = a

So,

lcm × hcf = 32 × a

=> 96 × 8 = 32 × a

=> 96 × 8 ÷ 32 = a

=> a = 24

Therefore the other no is = 24

Ans. 24

Hope it helps.