1. The least number which when divided by 4 , 5 and 6 leaves remainder 3 in each
case,
is
A. 64
B. 67
C. 71
D. 252
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67 is the correct answer
Here 4 –3 = 1, 5 – 3= 2, 6 – 3 = 3
∴ The required Number = LCM of (4, 5, 6) – 3
=>70-3=67
Here 4 –3 = 1, 5 – 3= 2, 6 – 3 = 3
∴ The required Number = LCM of (4, 5, 6) – 3
=>70-3=67
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