Question

1 . the length and breadth of a park is 30 m and 20 m respectively. find the perimeter and area of the park .

2. The side of the square garden is 16.5 metre find the perimeter and area.

3. the perimeter of Square garden is 42 find the side of the garden and also find its area.

4. The area of the badminton court is 60 m square . If it's length is 10 m , find its breadth and also find its area .

5. the perimeter of the whiteboard is 10 metre. if its breadth is 2 metre. find its length and also find its area.

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Answer 1

Step-by-step explanation:

1.Perimeter of park= 2(l+b).

perimeter= 2( 30+ 20)

perimeter= 2×50=100m

Area of park = l×b

area = 30×20

area= 600m^2

2.Perimeter = 4×side

= 4×16.5

= 66.0 m

Area = side × side

= 16.5× 16.5

= 272.25m^ 2

3.Perimeter= 4× side

42 unit= 4 × side

42/4 = side

10.5 unit= side

Area = side ×side

area= 10.5× 10.5

area = 110.25 unit^ 2

4.Area = l× b

60 m square = 10× b

60/10= b

6 = breadth

5. Perimeter= 2(l+b)

10m= 2(l+2)

10m = 2l+4

10-4= 2l

6=2l

6/2= 3m

Area = l×b

area = 3×2

area= 6m^2