1. The length and breadth of a rectangle are 10 cm and 8 cm respectively. Find its perimeter if the length and breadth are (i) doubled (ii) halved.
2. The parallel sides of a trapezium are 40 cm and 20 cm. If its non-parallel sides are both equal, each being 26 cm, find the area of the trapezium.
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1. Length of the rectangle = 10 cm
Breadth of the rectangle = 8 cm
(i) When they are doubled,
⇢l = 10 × 2 = 20 cm
⇢b = 8 × 2 = 16 cm
Perimeter = 2(l + b)
= 2(20 + 16)
= 2 × 36
= 72 cm
(ii) When they are halved,
⇢l = 10/2 = 5 cm
⇢b = 8/2 = 4 cm
Perimeter = 2(l + b)
= 2(5 + 4)
= 2 × 9
= 18 cm
Additional Information:
Here,
L is used for Length.
B is used for Breadth.
What is Perimeter?
The the length of the boundary of a closed figure is called the perimeter.
2. The parallel sides of an isosceles trapezium = 40 cm and 20 cm.
The equal sides = 26 cm.
The distance between the parallel sides = [26^2-{(40–20)/2}^2]^0.5
= [676–10^2]^0.5
= (676–100)^0.5
= 576^0.5
= 24 cm.
Area of trapezium = (40+20)*24/2 = 720 sq cm.
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