Question

1. The length and breadth of a rectangle are in the ratio 9:5. If its area is 720 m2, find its perimeter.

Answer 1

Step-by-step explanation:

$\huge\bold{\gray{\sf{Answer:}}}$

Explanation:

Given:

Length and breadth of a rectangle are in the ratio 9:5.Area is $720 {m}^{2}$.

To find :

Perimeter of the rectangle.

$\bold{\boxed{Area \: of \: Rectangle = length \times breadth}}$

Let the length of the rectangle be' 9x'

and breadth of the rectangle be '5x'

Now ,solving

$= > 9x \times 5x = 720 {m}^{2}$

$= > 45{x}^{2} = 720$

$= > {x}^{2} = \frac{720}{45} = 16$

$= > x = \sqrt{16} = 4m$

Length of the Rectangle=9x=9×4=$\bold{\red{36m}}$

Breadth of the rectangle=5x=5×4=$\bold{\red{20m}}$

Now,to find Perimeter of the rectangle

$\bold{\boxed{Perimeter \: of \: Rectangle = 2(l + b)}}$

$= 2(36 + 20) = 2(56) ={\red{ 112m}}$

Answer 2

ANSWER:

LENGTH OF THE RECTANGLE = 36m

BREADTH OF THE RECTANGLE = 20m

PERIMETER OF THE RECTANGLE = 112m

HOPE IT HELPS...