Question

1. The length and breadth of a rectangular field are in the ratio 9:5. If the area of the
field is 14580 square metre, find the cost of surrounding the field with a fence at the
rate of 3.25 per metre.
2. A rectangle is 16 m by 9 m. Find a side of the square whose area equals the area of
the rectangle. By how much does the perimeter of the rectangle exceed the perimeter
of the square?
3. Two adjacent sides of a parallelogram are 24 cm and 18 cm. If the distance between
longer sides is 12 cm, find the distance between shorter sides.​

Answer 1

Step-by-step explanation:

question 1 done on the uploaded page

Answer 2

length=9x

breadth=5x

Area = 9Xx5 X=14580

45x^2 =14580

x2 = 324

x =v324=18

l = 9x=162m

b = 5x=90m

Perimeter=2(I+b) = 2(162+90)

= 2x252=504m

COST of FENCING=504x3.25 =

Rs.1638. ANS

2)Area of Rectangle:

= 16x9=144m2. (IXb)

Area of square =144

Edge (a) of the square =v144=12m

perimeter of rectangle=

2 (I+b) = 2 (16+9)=50m

Perimeter of square:

4a = 4x12 = 48m

difference =50-48=2m. ANS

Area of parallelogram:

bh=24x12 = 288m2

Distance between shorterside:(h)

bxh=Area

I8xh=288

h =288/18=16m. ANS