Question

1. The length and breadth of a rectangular field are in the ratio 9:5. If the area of the field
is 14580 square metre, find the cost of surrounding the field with a fence at the rate of
33.25 per metre.
A rectangle is 16 mbym. Find a side of the square whose area canla​

Answer 1

Answer:

let the sides of rectangle be x, then

area of rectangle=l×b

9x×5x=14580

9x=14580/9

9x=1620

5x=14580/5

5x=2916

perimeter=2(l+b)

2(1620+2916)

2×4536

9027m

cost =9027×33.25

301644

Answer 2

Let the length of rectangle be 9x and its breadth be 5x

So,

Area = l × b

⇒ 14580 = 9x × 5x

45x2 = 14580

x2 = 14580/45 = 324

x = √324

x = 18

Hence,

Length = 9 × 18 = 162 m and Breadth = 5 × 18 = 90 m

Now, Perimeter = 2(l + b)

= 2 (162 + 90) = 2(252)

= 504 m.

Therefore, cost for fencing the surrounding 504 m at the rate of ₹3.25 per metre = ₹(504 × 3.25) = ₹1638

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