Question

1. The length, breadth and height of a cuboid are in the ratio 5: 3:2. If its volume is 240
cm3; find its dimensions. Also find the total surface area of a cuboid.
f dimensions​

Answer 1

Answer:

let all the sides be x

=5x,3x and 2x respectively.

5x+3x+2x=240cm^3(given)

10x=240cm^3

x=240/10

x=24

put value of x in all sides.

=5 (10)=50

3 (10)=30

2 (10)=20

TSA=2 (lb+bh+hl)

=2 [(50×30)+(30×20)+(20×50)]

=2×150+60+100

=620cm^3

Answer 2

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L → 10 cm

B → 6 cm

H → 4 cm

Total surface area → 248 cm³

_________________________

Let Length of cuboid → 5x

Let Breadth of cuboid → 3x

Let Height of cuboid → 2x

Volume of cuboid → L × B × H

240 = 5x × 3x × 2x

30x³ = 240

${x}^{3}=\frac{240}{30}$

x³ = 8

x = 2 cm

_________________________

Length of cuboid → 5 × 2 → 10 cm

Breadth of cuboid → 3 × 2 → 6 cm

Height of cuboid → 2 × 2 → 4 cm

_________________________

Total surface area of cuboid

→ 2 ( lb + bh + hl )

→ 2 ( 10 × 6 + 6 × 4 + 4 × 10 )

→ 2 ( 60 + 24 + 40 )

→ 2 ( 124 )

→ 248 cm²

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