Question

1. The length of a rectangle is 2 cm
more than its breadth, and its perimeter is 28 cm Find the length​

Answer 1

Answer :-

Length of the rectangle is 8 cm.

Solution :-

Let the breadth of the rectangle be x cm

Length of the rectangle = 2 cm more than the breadth = (x + 2) cm

Given

Perimeter of the rectangle = 28 cm

We know that

Perimeter of a rectangle = 2(Length + Breadth)

⇒ 2(x + 2 + x) = 28

⇒ 2(2x + 2) = 28

Transpose 2 to RHS (Multiplication becomes Division)

⇒ 2x + 2 = 28/2

⇒ 2x + 2 = 14

Transpose 2 to RHS (2 becomes - 2)

⇒ 2x = 14 - 2

⇒ 2x = 12

Transpose 2 to RHS (Multiplication becomes Division)

⇒ x = 12/2

⇒ x = 6

Breadth of the rectangle = x = 6 cm

Length of the rectangle = (x + 2) = (6 + 2) = 8 cm

Therefore length of the rectangle is 8 cm.

Answer 2

Answer:

length of the rectangle = 8cm

Explanation:

Given

Length of the triangle is 2cm more than its breadth

Perimeter = 28 cm

To Find

Length of the rectangle

Solution

let,

Breadth(b) = a cm

length(l) = (a+2) cm

As we know

$\boxed{\pink{Perimeter = 2(l+b)}}$

On putting the values

$\mathsf{2(a+2+a) = 28}$

$\mathsf{2(2a+2)= 28}$

$\mathsf{4(a+1)= 28}$

$\mathsf{a+1 = \dfrac{28}{4}}$

$\mathsf{a + 1= 7}$

$\mathsf{a = 7-1}$

$\mathsf{a = 6}$

Let us find the length

Length (l) = a+2

l = 6+2

l = 8cm