Question

1. the length of a rectangle is 2m more than it's breadth . if perimeter is 48m .then it's area in sq.m is​

Answer 1

Answer:

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Answer 2

ǫᴜᴇsᴛɪᴏɴ →

the length of a rectangle is 2m more than it's breadth . if perimeter is 48m .then it's area in sq.m is

ᴀɴsᴡᴇʀ →

Let breadth of the rectangle be 'b' cm.

So length of the rectangle will be 'b+2' cm.

Now

$\longmapsto\tt{Perimeter = 48}$

$\longmapsto\tt{2(l+b)=48}$

$\longmapsto\tt{2(b+2+b)=48}$

$\longmapsto\tt{2b+2=24}$

$\longmapsto\tt{2b=22}$

$\longmapsto\tt{b=11 \: cm}$

$\longmapsto\tt{l=b+2=13 \: cm}$

Then,

$\longmapsto\tt{Area \: of \: the \: rectangle = \: lb}$

$\longmapsto\tt{13×11}$

$\longmapsto\tt{143 \: cm²}$

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